This is about what i have read on article 19:
http://www.hardwaresecrets.com/article/19

The HyperTransport bus works at 3,200 MB/s in each direction...

This bus works at 800 MHz, transferring two 16-bit data per clock pulse, reaching a performance as if working at 1,600 MHz.

Now 1,600MHz giving 3,200 MB/s... Gabriel tell me if im right on my outlook.
This is because 1-bit of data is transfered per half hertz correct? 1-bit of data travels on the High end of the transmission Wave and 1-bit of data on the low end of the same wave correct? giving us 2-bits of data per clock pulse am i correct? 1Hz allways = 2bps?

Transfer rate = frequency in hertz x number of bits transferred per clock cycle / 8

Thus in this case:

Transfer rate = 1,600 x 16 / 8 = 3,200 MB/s

Cheers
Gabriel.

Thanks Gabriel, i got alittle contact high last night and it got me alittle off course, sorry about the silly question.

Hi,

Don't worry, there is no such thing as silly question!

Cheers,
Gabriel

Transfer rate = frequency in hertz x number of bits transferred per clock cycle / 8

Thus in this case:

Transfer rate = 1,600 x 16 / 8 = 3,200 MB/s

Cheers
Gabriel.

This goes back to my first post on this forum under the Video section, "Core clock being way lower then mem clock" you told me this:


an example of a memory running at 1,400 MHz. If the memory bus is of 256 bits, this equals to a transfer rate of 44.8 MB/s.

Compare this to a video card with a memory running at 700 MHz @ 128 bits: this equals to a transfer rate of 11.2 MB/s.

I can't make sence of the older quote's transfer rate, please explain how this works, I really am only asking because this is honestly confusing me not being rude in any way. Thanks bro.

an example of a memory running at 1,400 MHz. If the memory bus is of 256 bits, this equals to a transfer rate of 44.8 MB/s.

Transfer rate = frequency in hertz x number of bits transferred per clock cycle / 8

Thus:

Transfer rate = 1,400,000,000 x 256 / 8 = 44.8 GB/s (*)

Compare this to a video card with a memory running at 700 MHz @ 128 bits: this equals to a transfer rate of 11.2 MB/s.

Transfer rate = 700,000,000 x 128 / 8 = 11.2 GB/s (*)

(*) The rounding is wrong. 1 kilo = 2^10 and not 1,000; 1 mega = 2^20 and not 1,000,000 and 1 giga = 2^30 and not 1,000,000,000. All manufacturers use this wrong rounding, i.e. they consider 1 mega as 1 million and not as 1,048,576 (2^20) and 1 giga as 1 billion and not as 1,073,741,824. We need to follow them in order to make our numbers match theirs.

Cheers,
Gabriel.

Transfer rate = frequency in hertz x number of bits transferred per clock cycle / 8

Thus:

Transfer rate = 1,400,000,000 x 256 / 8 = 44.8 MB/s (*)



Transfer rate = 700,000,000 x 128 / 8 = 11.2 MB/s (*)

(*) The rounding is wrong. 1 kilo = 2^10 and not 1,000; 1 mega = 2^20 and not 1,000,000 and 1 giga = 2^30 and not 1,000,000,000. All manufacturers use this wrong rounding, i.e. they consider 1 mega as 1 million and not as 1,048,576 (2^20). We need to follow them in order to make our numbers match theirs.

Cheers,
Gabriel.

Oh i know its not exactly 1,000,000,000 bro, its just that when i calculate for these transfer rates in rounding im coming up with 1,400,000,000 x 256 / 8 = 44.8 GB/s not 44.8 MB/s, just checking if i was doing something wrong but im doing it as you say and still getting same results. Same for Transfer rate = 700,000,000 x 128 / 8 = 11.2 GB/s and not MB/s when i do the math out, are you sure its in Megs? if so how am i coming up with Gigs? Reason im askin such questions is because i have done work such as this for awhile now and and these rates are confusing me as they should come up in different numerical rates such as GB/s should they not?

Gosh! I think I was sleeping or something like this. It is GB/s of course, not MB/s. My bad. Let's fix the messages...

Cheers,
Gabriel.

Ok bro sounds good, thanks for clearing all that up :)

"There is no such thing as silly question." Very philosophical indeed.